python如何表示一周连续工作四天

python如何表示一周连续工作四天？

代码示例：

#!/usr/bin/env python

# -*- coding:utf-8 -*-

import datetime

import collections

def date_list_fun(starttime,endtime):

'''计算输入的起始日期和结束日期之间的所有日期'''

_u=datetime.timedelta(days=1)

startdate=datetime.datetime.strptime(starttime,'%Y%m%d')

enddate=datetime.datetime.strptime(endtime,'%Y%m%d')

n=0

date_list=[]

if startdate=enddate:

# print startdate,enddate

while 1:

_time=startdate+n*_u

date_list.append(_time.strftime('%Y%m%d'))

n=n+1

if _time==enddate:

break

return date_list

def allweeks(year):

'''计算一年内所有周的具体日期,从1月1号开始，12.31号结束

输出如{ 1: ['20190101','20190106'],...} 只有六天

'''

start_date=datetime.datetime.strptime(str(year)+'0101','%Y%m%d')

end_date=datetime.datetime.strptime(str(year)+'1231','%Y%m%d')

_u=datetime.timedelta(days=1)

n=0

week_date={ }

while 1:

_time=start_date+n*_u

w=str(int(_time.strftime('%W'))+1)

week_date.setdefault(w,[]).append(_time.strftime('%Y%m%d'))

n=n+1

if _time==end_date:

break

week_date_start_end={ }

for i in week_date:

week_date_start_end[i]=[week_date[i][0],week_date[i][-1]]

print week_date

print week_date_start_end

return week_date

def all_weeks(year):

'''计算一年内所有周的具体日期,每周都是7天，可能最后一周到 下年

week_date 输出如{ 1: ['20181231', '20190101', '20190102', '20190103', '20190104', '20190105', '20190106'],...}

计算一年内所有周的起始日期

week_date_start_end { 1: ['20181231','20190106'],...}

'''

start_date=datetime.datetime.strptime(str(int(year)-1)+'1224','%Y%m%d')

end_date=datetime.datetime.strptime(str(int(year)+1)+'0107','%Y%m%d')

_u=datetime.timedelta(days=1)

n=0

week_date={ }

while 1:

_time=start_date+n*_u

y,w=_time.isocalendar()[:2]

if y==year :

week_date.setdefault(w,[]).append(_time.strftime('%Y%m%d'))

n=n+1

if _time==end_date:

break

week_date_start_end={ }

for i in week_date:

week_date_start_end[i]=[week_date[i][0],week_date[i][-1]]

print week_date

# print week_date_start_end

return week_date,week_date_start_end

声明：本文内容由网友自发贡献，本站不承担相应法律责任。对本内容有异议或投诉，请联系2913721942#qq.com核实处理，我们将尽快回复您，谢谢合作！