PostgreSQL 查找当前数据库的所有表操作

实现的功能类似MySQL：

show tables;

在 PostgreSQL 中需要写：

select * From pg_tables where schemaname = 'public';

返回结果类似如下：

schemaname | tablename | tableowner | tablespace | hasindexes | hasrules | hastriggers | rowsecurITy ------------+-----------+------------+------------+------------+----------+-------------+------------- public  | deploy | postgres |   | t   | f  | f   | f public  | deploy2 | postgres |   | f   | f  | f   | f(2 rows)@H_126_16@
补充：PostgreSql 获取所有的表、视图、字段、 主键
PostgreSQL获取数据库中所有view名 视图：
SELECT viewname From pg_views WHERE  schemaname ='public' 
postgreSQL获取数据库中所有table名 表：
SELECT tablename FROM pg_tables WHERE tablename NOT LIKE 'pg%' AND tablename NOT LIKE 'sql_%'ORDER BY tablename;
    
postgreSQL获取某个表tablename 所有字段名称 ， 类型，备注,是否为空 等
SELECT col_description(a.attrelid,a.attnum) as comment,pg_tyPE.typname as typename,a.attname as name, a.attnotnull as notnullFROM pg_class as c,pg_attribute as a inner join pg_type on pg_type.oid = a.atttypidwhere c.relname = 'tablename' and a.attrelid = c.oid and a.attnum>
    0
postgreSQL获取某个表tablename 的主键信息
select pg_attribute.attname as colname,pg_type.typname as typename,pg_constraint.conname as pk_name from pg_constraint inner join pg_class on pg_constraint.conrelid = pg_class.oid inner join pg_attribute on pg_attribute.attrelid = pg_class.oid and pg_attribute.attnum = pg_constraint.conkey[1]inner join pg_type on pg_type.oid = pg_attribute.atttypidwhere pg_class.relname = 'tablename' and pg_constraint.contype='p'
以上为个人经验，希望能给大家一个参考，也希望大家多多支持。如有错误或未考虑完全的地方，望不吝赐教。
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