首页主机资讯C语言reverse二进制位的实现

C语言reverse二进制位的实现

时间2024-06-24 23:06:03发布访客分类主机资讯浏览1432
导读:#include <stdio.h> unsigned int reverseBits(unsigned int num { unsigned int count = sizeof(num * 8 - 1;...

#include <
    stdio.h>


unsigned int reverseBits(unsigned int num) {
    
    unsigned int count = sizeof(num) * 8 - 1;
    
    unsigned int reverse_num = num;
    
    
    num >
    >
    = 1;

    while (num) {
    
        reverse_num <
    <
    = 1;
    
        reverse_num |= num &
     1;
    
        num >
    >
    = 1;
    
        count--;

    }
    

    reverse_num <
    <
    = count;
    
    return reverse_num;

}


int main() {
    
    unsigned int num = 10;
     // 00000000000000000000000000001010
    unsigned int reversed_num = reverseBits(num);
    

    printf("Original number: %u\n", num);
    
    printf("Reversed number: %u\n", reversed_num);
    

    return 0;

}
    

这段代码实现了一个函数reverseBits,用于将一个无符号整数中的二进制位逆序。在main函数中,我们定义了一个初始值为10的无符号整数,将其二进制位翻转后输出。

声明:本文内容由网友自发贡献,本站不承担相应法律责任。对本内容有异议或投诉,请联系2913721942#qq.com核实处理,我们将尽快回复您,谢谢合作!


若转载请注明出处: C语言reverse二进制位的实现
本文地址: https://pptw.com/jishu/683906.html
配置apache2服务器_基线检查 C语言reverse如何确保效率

游客 回复需填写必要信息